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force of falling object
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Dear convert-me.com forum visitors,
Our forum has been available for many years. In September 2014 we decided to switch it to read-only mode. Month after month we saw less posts with questions and answers from real people and more spam posts. We were spending more and more resources cleaning the spam until there were less them 1 legitimate message per 100 spam posts. Then we decided it's time to stop.
All the posts in the forum will be available and searchable. We understand there are a lot of useful information and we aren't going to remove anything. As for the new questions, you can always ask them on convert-me.com FaceBook page
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force of falling object
by jmpal » Wed Jan 19, 2011 8:56 am
If a 5 lb block of ice fell from 30' how much force would it have on impact?
- jmpal
Re: force of falling object
by Guest » Mon Jan 09, 2012 7:14 am
2012.1.8
F=Mass x Accel
free falling body, uniform acceleration (Newton's 2nd Law) F=mg (g = gravitational field strength)
So, from physics we can use the formula for constant acceleration: x - x0 = v0 * t + 1/2 a*t*t
velocity = v = sqrt(2gh)
time = t = sqrt(2h/g)
v= sqrt(2 x 32 ft/s/s x 30 ft) = 43.81 ft per sec
t= sqrt(2 x 30 / 32) = 1.369 sec
From these formulas, an object would take 1.37 seconds to fall 30 feet, and would be traveling 43.8 ft/s when it gets there.
F = 5 lbs x 43.8 ft/s = 219 pound-force (lbf)
F=Mass x Accel
free falling body, uniform acceleration (Newton's 2nd Law) F=mg (g = gravitational field strength)
So, from physics we can use the formula for constant acceleration: x - x0 = v0 * t + 1/2 a*t*t
velocity = v = sqrt(2gh)
time = t = sqrt(2h/g)
v= sqrt(2 x 32 ft/s/s x 30 ft) = 43.81 ft per sec
t= sqrt(2 x 30 / 32) = 1.369 sec
From these formulas, an object would take 1.37 seconds to fall 30 feet, and would be traveling 43.8 ft/s when it gets there.
F = 5 lbs x 43.8 ft/s = 219 pound-force (lbf)
- Guest
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