by Dennijs » Tue May 07, 2013 10:54 am
A 12'x2.25' diameter cylinder (with flat ends) would have a volume of 47.713 ft^3. Usually gas tanks have domed ends, so I'm going to assume that the two ends would combine to a sphere with radius 2.25'/2 =1.125'. That would leave the length of the cylindrical part to be 9.75' (12.0' - 1.125' - 1.125').
Let L = 9.75', r = 1.125'
So the volume would be that of the cylinder plus that of the sphere: (L * Pi * L^2) + ((4/3) * Pi * r^3) = 44.73 ft^3.
If it were a pure cylinder the volume would be: 12' * Pi * r^2 = 47.713 ft^3.
You're holding liquid fuel, so you would have a different amount of gallons per cubic foot that was provided earlier (35.97 CuFt / 1 Gallon).
It would take 7.48 liquid gallons to fill 1 cubic foot. Just convert inches to centimeters and liters to gallons to determine that!
So a 12'x2.25' cylinder would hold 47.713 ft^3 * 7.48 gal/ft^3 = 356.9 gallons.
The domed end tank would hold 44.73 ft^3 * 7.48 gal/ft^3 = 334.6 gallons.
I may be a little off, but I think I'm right on this!