Please help with this
D1 gravel for road
7000 feet long 30' wide with 6"D1
7000' x 30' x 6" = 1,260,000 ( cubic inches? or cubic FT ?)
Do I divide or multiply by 12 to get cubic FT? and then divide or multiply by 27 to get CY then multiply or divide by 1.6 ( coefficent for D1 of tons per CY) to equal tons?????
thanks
drh
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Dear convert-me.com forum visitors,
Our forum has been available for many years. In September 2014 we decided to switch it to read-only mode. Month after month we saw less posts with questions and answers from real people and more spam posts. We were spending more and more resources cleaning the spam until there were less them 1 legitimate message per 100 spam posts. Then we decided it's time to stop.
All the posts in the forum will be available and searchable. We understand there are a lot of useful information and we aren't going to remove anything. As for the new questions, you can always ask them on convert-me.com FaceBook page
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by Dirtman » Sat Apr 28, 2007 11:48 am
D1 gravel for road
7000 feet long 30' wide with 6"D1
7000' x 30' x 6" = 1,260,000 ( cubic inches? or cubic FT ?)
It's neither cubic feet or cubic inches, but a mix. An easy way to obtain cubic feet is to let all factors be in feet. To convert inches to decimal feet, divide inches by 12, e.g., 6 inches / 12 = 0.5 feet.
So: 7000' * 30' * 0.5' = 105,000 cf (cubic feet)
Do I divide or multiply by 12 to get cubic FT? and then divide or multiply by 27 to get CY then multiply or divide by 1.6 ( coefficent for D1 of tons per CY) to equal tons?????
To obtain cubic yards from cubic feet, divide cubic feet by 27, so: 105,000 cubic feet / 27 = 3,888.89 cubic yards.
You have a volume to weight factor (D1) of 1.6, so: 3,888.89 cubic yards * 1.6 = 6,222.22 tons
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