I need to conver 20.2 lbs per hour to scfm can anyone help?
thanks
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pounds per hour to scfm
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Our forum has been available for many years. In September 2014 we decided to switch it to read-only mode. Month after month we saw less posts with questions and answers from real people and more spam posts. We were spending more and more resources cleaning the spam until there were less them 1 legitimate message per 100 spam posts. Then we decided it's time to stop.
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pph to scfm
by keith » Mon May 23, 2005 4:55 pm
Anonymous wrote:You need to know the density at the "standard" conditions (the "s" in scfm). The hours and minutes are trivial.
gas is nitrogen at approx. 70f can this be used to calculate approx. value?
- keith
by Guest » Mon May 23, 2005 6:23 pm
Yes, that's enough. The density of any gas is
rho = MP/RT
M is the molecular weight, 28.02 u
P is the pressure, 1 atm is normal for "standard conditions"
T is the absolute temperature. 60 °F and 68 °F are the usual "standard" temperatures in english unit gas measure. We'll assume 68 °F and convert it to Rankine, 527.7 R.
R is the gas constant, in English units, is 0.7302 atm-ft^3/(lbmol-R)
rho = 28.02 lb/mol x 1 atm/ (0.7302 atm-ft^3/(lbmol-R) x 527.7 R) = 0.0727 lb/ft^3.
Then 20.2 lb/hr x 1hr/60 min x 1 ft^3/.0727 lbs = 4.63 ft^3/m. Since I used the pressure and temp. of standard conditions, those are scfm.
rho = MP/RT
M is the molecular weight, 28.02 u
P is the pressure, 1 atm is normal for "standard conditions"
T is the absolute temperature. 60 °F and 68 °F are the usual "standard" temperatures in english unit gas measure. We'll assume 68 °F and convert it to Rankine, 527.7 R.
R is the gas constant, in English units, is 0.7302 atm-ft^3/(lbmol-R)
rho = 28.02 lb/mol x 1 atm/ (0.7302 atm-ft^3/(lbmol-R) x 527.7 R) = 0.0727 lb/ft^3.
Then 20.2 lb/hr x 1hr/60 min x 1 ft^3/.0727 lbs = 4.63 ft^3/m. Since I used the pressure and temp. of standard conditions, those are scfm.
- Guest
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5 posts
• Page 1 of 1