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need help with this one
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Dear convert-me.com forum visitors,
Our forum has been available for many years. In September 2014 we decided to switch it to read-only mode. Month after month we saw less posts with questions and answers from real people and more spam posts. We were spending more and more resources cleaning the spam until there were less them 1 legitimate message per 100 spam posts. Then we decided it's time to stop.
All the posts in the forum will be available and searchable. We understand there are a lot of useful information and we aren't going to remove anything. As for the new questions, you can always ask them on convert-me.com FaceBook page
Thank you for being with us and sorry for any inconveniences this could caused.
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need help with this one
by hoppnjoe » Sat Aug 28, 2010 5:27 am
heres what i need to find out. I have 8 oz of liquid that i need to mix with 24 gals, and only have a 2 gal sprayer. Please help. I dont want to burn up my new lawn. thanks so much
- hoppnjoe
Re: need help with this one
by spider » Sat Aug 28, 2010 7:44 am
The calculation is as follows:
8 oz. corresponds to 24 gallons
as
x oz. corresponds to 2 gallons.
Then, x = 2 gallons * 8 oz. / 24 gallons = 16 oz. / 24 = 0.666666 oz.
The answer is, you need to use 0.666666 oz. of your liquid for your 2 gal. sprayer.
8 oz. corresponds to 24 gallons
as
x oz. corresponds to 2 gallons.
Then, x = 2 gallons * 8 oz. / 24 gallons = 16 oz. / 24 = 0.666666 oz.
The answer is, you need to use 0.666666 oz. of your liquid for your 2 gal. sprayer.
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