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Convert Amperage to Temperature?
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Dear convert-me.com forum visitors,
Our forum has been available for many years. In September 2014 we decided to switch it to read-only mode. Month after month we saw less posts with questions and answers from real people and more spam posts. We were spending more and more resources cleaning the spam until there were less them 1 legitimate message per 100 spam posts. Then we decided it's time to stop.
All the posts in the forum will be available and searchable. We understand there are a lot of useful information and we aren't going to remove anything. As for the new questions, you can always ask them on convert-me.com FaceBook page
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Convert Amperage to Temperature?
by PipePurger » Tue Mar 16, 2010 12:43 am
If someone could help. We have special, heat resistant (aluminum) tape for the welding industry. Based on the 2 sizes/thicknesses involved - one is rated at a maximum use (limit) of 130 amps and the other is rated at a maximum use (limit) of 250 amps. I am frequently asked what the temperature limits are for these tapes - and I don't have an answer, nor do I know what conversion method/formula to use... Anyone?? (Fahrenheit or Celsius is okay)
- PipePurger
- Posts: 2
- Joined: Tue Mar 16, 2010 12:25 am
Re: Convert Amperage to Temperature?
by babymathew » Fri Jul 09, 2010 1:14 pm
Not sure, but a thought that came up is
by a combination of known equations:
I am not sure but i think this will help you,
(1) DT=DQ/mc,
DT=Difference in temperature (Kelvin)
DQ=Difference in heat (Joule)
m=mass (kg)
c=specific heat (J/K*kg)
(the increase in temperature is equal to the transfered heat divided by the mass of the object and its specific heat).
(2) 1J=1W* 1s
J=joule
W=watt
s=second
By inserting (2) in (1) you get the relation between watt and celcius (Celcius=Kelvin-273).
by a combination of known equations:
I am not sure but i think this will help you,
(1) DT=DQ/mc,
DT=Difference in temperature (Kelvin)
DQ=Difference in heat (Joule)
m=mass (kg)
c=specific heat (J/K*kg)
(the increase in temperature is equal to the transfered heat divided by the mass of the object and its specific heat).
(2) 1J=1W* 1s
J=joule
W=watt
s=second
By inserting (2) in (1) you get the relation between watt and celcius (Celcius=Kelvin-273).
- babymathew
- Posts: 4
- Joined: Fri Jul 09, 2010 9:56 am
More info
2 posts
• Page 1 of 1