HELP - what is the calculation for the following
80 drums
each are 24 x 24 x 35
I'm calculating by multiplying each drum size by 80 = 1920 x 1920 x 2800 then dividing by 1728. Why isn't it working? (5973333.33)
If I use 24 x 24 x 35 = 20160 divided by 1728 = 11.6667 x 80 = 933.33 which is the correct answer.
What should I use as my 3 figures multiplied and divided by 1728 to get the proper calculation????
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Inches to Cubic Ft/Meter
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Inches to Cubic Ft/Meter
by MMG » Fri Apr 15, 2005 11:02 pm
- MMG
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- Joined: Fri Apr 15, 2005 10:51 pm
by Guest » Fri Apr 15, 2005 11:28 pm
80 drums are 80X as big as one drum; so compute one drum and multiply by 80. If you multiply each of three dimensions by 80, that is 80^3 = 512,000X bigger.
Also, exactly what are you computing? "Drums" are usually cylindrical. If the drum is 24" diameter x 35" high, you are using the wrong formula for volume (V = (pi/4)*d^2*h). I suppose rectangular solid drums are possible though.
Also, exactly what are you computing? "Drums" are usually cylindrical. If the drum is 24" diameter x 35" high, you are using the wrong formula for volume (V = (pi/4)*d^2*h). I suppose rectangular solid drums are possible though.
- Guest
Inches to Cubic Ft/Meter
by MMG » Fri Apr 15, 2005 11:35 pm
We have software that is supposed to calculate for us. We enter the inches _x_x_ In the case of 1 pallet we multiply the inches of the pallet x how many pallets we are using and it gives the proper cubic feet/meters. In the case of single drums multiplying each dimension by (in this case) 80 doesn't work. Should I be entering different values into these fields?
- MMG
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- Joined: Fri Apr 15, 2005 10:51 pm
by Guest » Sat Apr 16, 2005 12:06 am
I have no idea how your software is designed, but the volume of n pallets, each l x w x h is n*l*w*h, ie you multiply by the number of pallets once, not three times. Also the computer should do the math, you certainly shouldn't have to do any multiplying, by hand. If you do, you may as well use your calculator and not buy software.
As for round drums, if you strap them to a square pallet, equal to a diameter for ease of forking, this is the room they'd take. However, in a close packed hexagonal array, you could get as much as 21.46% more drums in the same space (you won't do quite that well due to lost space at the ends of the rows, but you should get 15-20% more drums in the same space, optimally packed.
As for round drums, if you strap them to a square pallet, equal to a diameter for ease of forking, this is the room they'd take. However, in a close packed hexagonal array, you could get as much as 21.46% more drums in the same space (you won't do quite that well due to lost space at the ends of the rows, but you should get 15-20% more drums in the same space, optimally packed.
- Guest
Re: Inches to Cubic Ft/Meter
by Guest » Sat Apr 16, 2005 12:13 am
MMG wrote:
If I use 24 x 24 x 35 = 20160 divided by 1728 = 11.6667 x 80 = 933.33 which is the correct answer.
What should I use as my 3 figures multiplied and divided by 1728 to get the proper calculation????
You need four figures
(80 x 24" x 24" x 35")/1728 in^3/ft^3= 933.3 cu ft.
933.3 cu ft. x 0.0283168 m^3/ft^3 = 26.43 m^3
- Guest
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